In the opposite figure:
\(ABCD\) is an isosceles trapezium in which:
\[ AB = AD = DC = 5 \, \text{cm}, \, BC = 11 \, \text{cm} \]
\(ABCD\) is an isosceles trapezium in which:
\[ AB = AD = DC = 5 \, \text{cm}, \, BC = 11 \, \text{cm} \]
Find:
- \( m(\angle B) \), \( m(\angle A) \)
- The area of the trapezium \( ABCD \)
- 53° 7' 48", 126° 52' 12"
- 32 cm²
MR/Nasef.N

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