Given the ratios: \(\frac{a + b}{4} = \frac{b + c}{5} = \frac{c + a}{7}\)
Prove that: \(\frac{a+b+c}{8} = \frac{a}{3}\)
Adding the antecedents and consequents of the three ratios.
Then Multiplying the terms of the \(2^{\text{nd}}\) ratio by \((-1)\) and adding the antecedents and consequents of the \(1^{\text{st}}\) and \(2^{\text{nd}}\) ratios.
Then Multiplying the terms of the \(2^{\text{nd}}\) ratio by \((-1)\) and adding the antecedents and consequents of the \(1^{\text{st}}\) and \(2^{\text{nd}}\) ratios.
MR/Nasef.N
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