Given: \(\frac{x}{3} = \frac{y}{4} = \frac{z}{5}\)
a) Prove that: \(\frac{2y - z}{3x - 2y + z} = \frac{1}{2}\)
Let \(\frac{x}{3} = \frac{y}{4} = \frac{z}{5}\) = m where \(m > 0\)
∴ \(x = 3 \, \text{m}, \, y = 4 \, \text{m}, \, z = 5 \, \text{m}\)
∴ \(x = 3 \, \text{m}, \, y = 4 \, \text{m}, \, z = 5 \, \text{m}\)
MR/Nasef.N
b) Prove that: \(\sqrt[3]{3x^2 + 3y^2 + z^2} = 2x + y\)
Let \(\frac{x}{3} = \frac{y}{4} = \frac{z}{5}\) = m where \(m > 0\)
∴ \(x = 3 \, \text{m}, \, y = 4 \, \text{m}, \, z = 5 \, \text{m}\)
∴ \(x = 3 \, \text{m}, \, y = 4 \, \text{m}, \, z = 5 \, \text{m}\)
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