a) Solve the system of equations:
\[\frac{x}{6} + \frac{y}{3} = \frac{1}{3}\]
\[\frac{x}{2} + \frac{2y}{3} = 1\]
Solution: (2, 0)
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b) Which point satisfies both equations?
\[\frac{x}{6} + \frac{y}{3} = \frac{1}{3}\]
\[\frac{x}{2} + \frac{2y}{3} = 1\]
b
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