Friday, April 18, 2025

Q13 Prep 3 Algebra Question Bank

Graphing Functions Solutions
a) For the function \( f(x) = -x^2 + 6x - 11 \) in the interval \([0, 6]\), find:
The solution set of \( x^2 - 6x + 11 = 0 \)
∴ The S.S. = \( \emptyset \) (No real solutions)
b) For the function \( f(x) = 6x - x^2 - 9 \) in the interval \([0, 5]\), find:
  1. The maximum or minimum value of the function
  2. The solution set of \( 6x - x^2 - 9 = 0 \)
1. Maximum value: \( 0 \) at \( x = 3 \)
2. ∴ The S.S. = \( \{3\} \) (Double root)



MR/Nasef.N

No comments:

Post a Comment