Sunday, June 2, 2024

(Q2) (1-1 ) solving quadratic equation in one variable.

 

1sec First term  Algebra Unit 1  (1-1 )  solving quadratic equation in one variable.


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(Q2)

Challenging Math Question

Choose

The equation: \( (x - 3)(x + 4)(x - 1) = 0 \) is of what degree?

  1. First
  2. Second
  3. Third
  4. Fourth
الأسئلة الشائعة

(3).

Solution to Challenging Math Question

Solution

1. Expand the equation to determine its degree.
2. \( (x - 3)(x + 4)(x - 1) = 0 \)
3. Multiplying the factors:
- First, \( (x - 3)(x + 4) = x^2 + x - 12 \)
- Then, \( (x^2 + x - 12)(x - 1) \)
4. The highest power of \( x \) in the resulting polynomial \( x^3 - x^2 - 13x + 12 \) is 3.

Therefore, the correct answer is: Third

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